gradient = \( \frac {\text{change in y}}{\text{change in x}} = \frac {\text{change in speed}}{\text{change in time}}\) \( = \frac {\text{change in metres per second ...

This is a classic introductory physics problem. Basically, you have a cart on a frictionless track (call this m 1) with a string that runs over a pulley to another mass hanging below (call this m 2).

gradient = \(\frac{change~in~y}{change~in~x} = \frac{change~in~speed}{change~in~time} = \) \( \frac{change~in~metres~per~second}{change~in~seconds}\) = metres per ...